LoL, had my brother talk to me about that mathmatic with me a while ago (he's at university studying 2 maths courses ). He also showed me an algebraic formula that can proove that 1 = 2, therefore 2 = 5 and therefore 10 = 1
Words
n = 0.9999999999^INF
10n = 10 (0.9999999999^INF)
9n = 10n - n
= 10 (0.9999999999^INF) - 0.9999999999^INF
= 0.9999999999^INF
Therefor n = 0.9999999999^INF
???
n = 0.9999999999^INF
10n = 10 (0.9999999999^INF)
9n = 10n - n
= 10 (0.9999999999^INF) - 0.9999999999^INF
= 0.9999999999^INF
Multiplication always comes before subtration otherwise you would have ended up with 10 x 0 = 0 and not "n = 0.9999999999^INF". I dont know what the hell you did but it's wrong.
9n = 10n - n
= 10 (0.9999999999^INF) - 0.9999999999^INF
= 0.9999999999^INF
Therefor n = 0.9999999999^INF
???
Incorrect!
[...]
Multiplication always comes before subtration otherwise you would have ended up with 10 x 0 = 0 and not "n = 0.9999999999^INF". I dont know what the hell you did but it's wrong.
Ahey,
By the way, if I may ask, why did you feel the urge to prove that 1=1?
Cheers,
J.
9n = 10n - n
= 10 (0.9999999999^INF) - 0.9999999999^INF
= 9 (0.9999999999^INF)
Therefor n = 0.9999999999^INF
That is what he meant, and that is, in fact, correct.
.9999^inf=0 anyway